Dear Sir,
We had 150mm MS pipe line 1000 mtr long laid at 2 degree angle or at slope 0-36 mtr. We have to pump water in upward direction. What I wish to know is how much pressure is required to be generated by pump to get flow rate of 40-45 cu mtr per hr.
Also pls confirm relation between head, flow rate and maximum pressure developed/sustained by a pump
Regds
RRKrrklntecc
Posts: 1
Joined: Mon Jun 06, 2011 3:51 pm Top
PRESSURE REQUIREMENT
Re: PRESSURE REQUIREMENT
For your problem you can use pressure drop calculator at:
http://www.pipeflowcalculations.com/pressuredrop/
There you should enter flow rate, pipe diameter, pipe length and calculate pressure drop like this:
Calculation report
Pipe pressure drop calculator
1. volume flow rate (q):
q : 40 m3/h
2. weight flow rate (w):
w : 40000.004 kg/h
3. pipe length (L):
L : 1000 m
4. pipe diameter (D):
D : 150 mm
5. pipe roughness (kr):
kr : 0.1 mm
6. density (ρ):
ρ : 1000 kg/m3
7. kinematic viscosity (ν):
ν : 1.006 mm2/s
8. dynamic viscosity (μ):
μ : 0.0010060001 Pas
9. K factor - minor losses coefficient (K ):
K : 0.0
10. velocity (V):
V : 0.6287607 m/s
11. cross section area (A):
A : 17671.46 mm2
12. friction coefficient (f):
f : 0.018081807
13. Reynolds number (Re):
Re : 93751.59
14. boundary layer (δ):
δ : 0.41964057 mm
17. pressure drop (p1-p2):
p1-p2 : 0.23828205 bar
So, due to friction pressure drop is 0.24 bar.
To overcome geodetic height of 36 m, additional 3.53 bar is needed (rho * g * h = 1000 * 9.81 * 36 = 3.53 bar), so pump must generate 0.24 + 3.53 = 3.77 bar at 40 m3/h.
For this kind of problems you should use Bernoulli equation together with Darcy equation, which you can find at:
http://www.pipeflowcalculations.com/pip ... fluids.php
http://www.pipeflowcalculations.com/pip ... fluids.php
http://www.pipeflowcalculations.com/pip ... heorem.php
http://www.pipeflowcalculations.com/pressuredrop/
There you should enter flow rate, pipe diameter, pipe length and calculate pressure drop like this:
Calculation report
Pipe pressure drop calculator
1. volume flow rate (q):
q : 40 m3/h
2. weight flow rate (w):
w : 40000.004 kg/h
3. pipe length (L):
L : 1000 m
4. pipe diameter (D):
D : 150 mm
5. pipe roughness (kr):
kr : 0.1 mm
6. density (ρ):
ρ : 1000 kg/m3
7. kinematic viscosity (ν):
ν : 1.006 mm2/s
8. dynamic viscosity (μ):
μ : 0.0010060001 Pas
9. K factor - minor losses coefficient (K ):
K : 0.0
10. velocity (V):
V : 0.6287607 m/s
11. cross section area (A):
A : 17671.46 mm2
12. friction coefficient (f):
f : 0.018081807
13. Reynolds number (Re):
Re : 93751.59
14. boundary layer (δ):
δ : 0.41964057 mm
17. pressure drop (p1-p2):
p1-p2 : 0.23828205 bar
So, due to friction pressure drop is 0.24 bar.
To overcome geodetic height of 36 m, additional 3.53 bar is needed (rho * g * h = 1000 * 9.81 * 36 = 3.53 bar), so pump must generate 0.24 + 3.53 = 3.77 bar at 40 m3/h.
For this kind of problems you should use Bernoulli equation together with Darcy equation, which you can find at:
http://www.pipeflowcalculations.com/pip ... fluids.php
http://www.pipeflowcalculations.com/pip ... fluids.php
http://www.pipeflowcalculations.com/pip ... heorem.php
Pipe flow calculations - since 2000