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- Joined: Wed Mar 29, 2017 1:11 am
Assume the pressure in a 3/4 inch natural pipe line (.824 I.D.) remains constant at 150 psig.; what is the thrust/force created as the gas exits the 3/4 inch open line?
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It is density x velocity^2 x area
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- Joined: Thu Mar 30, 2017 8:31 am
that should be the product of dynamic pressure and the area of the Pipe;
Force = (1/2 x Density x velocity^2) x (0.7854 x dia^2)