Hello, cool site

Here is the run down first, I'm trying to find a min mass flow rate for my project which needs to be 1 GPM, and max 4 GPM. Now water is going out of a 5 gallon jug, that has the top cut off, and the water is flowing into a PVC pipe. The area is already set at 1.5 inches, which I know is to big. I need to find the velocity of water at atm pressure, and then the diameter of the circle which the water will funnel through. I did some work I just need help making sure I did it right, basically a check over. think of it as a Deer Park 5 gallon bottle, like the ones for water dispenser, but the top cut off, and it flowing out the nozzle.

19.5 fluid height.

So, I know V=sqrt(2∗19.5inches∗387.6inches/s^2)

V=122.95 inches/sec, 10.245 ft/s = 614.7 ft/min

Now the simple equation of Q=VA

1 GPM->.13ft^3/min = 614.7ft/min * A

.03024 in^2 = A(min)

sqrt(.03024/∏)= r(min) = .09811 inches

We would have to reduce our inner diameter to .19622 inches.

Now is this right? I can't believe that? I was initial thinking it would be a DE since our mass flow would be varying, depending the height of the water, gravity would be pushing it through the main system. I hope it is steady state much easier.

## Mass Flow rate through gallon/check over equation

### Re: Mass Flow rate through gallon/check over equation

picture to clear things up.